10 resistors, each of resistance R , are connected in series to a battery of EMF E and negligible internal resistance. When they are instead connected - Physics MCQ NEET 2023 2026 | ExamTest.live

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10 resistors, each of resistance R, are connected in series to a battery of EMF E and negligible internal resistance. When they are instead connected in parallel to the same battery, the current increases n times. The value of n is:

Solution & Step-by-step Explanation

Series: R_{s} = 10 R . Current I_{s} = \frac{E}{10 R} .Parallel: R_{p} = \frac{R}{10} . Current I_{p} = \frac{E}{R /10} = \frac{10 E}{R} .Comparing the currents: I_{p} = 100 \times (\frac{E}{10 R}) = 100 I_{s} So, n = 100 .

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10 resistors, each of resistance R, are connected in series to a battery of EMF E and negligible internal resistance. When they are instead connected in parallel to the same battery, the current increases n times. The value of n is:

10

100

1

1000

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