$119^2-111^2$ is a/an:

Let's use the algebraic identity $a^2-b^2=(a-b)(a+b)$:
$$119^2-111^2=(119-111)(119+111)$$
$$119^2-111^2=(8)\times (230)=1840$$
Let's check the nature of $1840$:It is not a perfect square (since it ends in a single zero).It is not a prime number (it is even and has multiple factors).It is an even number greater than $2$, so it is clearly a composite number.