$4d,5p,5f$ and $6p$ orbitals are arranged in the order of decreasing energy. The correct option is:

According to the $(n+l)$ rule, higher $(n+l)$ values mean higher energy. If $(n+l)$ is the same, the one with higher $n$ has higher energy.$5f$: $n=5,l=3⟹n+l=8$$6p$: $n=6,l=1⟹n+l=7$$5p$: $n=5,l=1⟹n+l=6$$4d$: $n=4,l=2⟹n+l=6$ Between $5p$ and $4d$, $5p$ has higher $n$, so $5p>4d$.Energy order: $5f>6p>5p>4d$.