6.02 × 10^20 molecules of urea are present in 100\ ml of its solution. The concentration of the urea solution is: - Chemistry MCQ AIEEE 2004 2026 | ExamTest.live

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6.02 \times 1 0^{20} molecules of urea are present in 100 ml of its solution. The concentration of the urea solution is:

Solution & Step-by-step Explanation

Number of moles of urea = \frac{Number of molecules}{Avogadro’s number} = \frac{6.02 \times 1 0 ^{20}}{6.02 \times 1 0 ^{23}} = 1 0^{- 3} moles = 0.001 moles . Volume of solution = 100 ml = 0.1 L . Molarity = \frac{moles}{volume in L} = \frac{0.001}{0.1} = 0.01 M .

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6.02 \times 1 0^{20} molecules of urea are present in 100 ml of its solution. The concentration of the urea solution is:

0.001 M

0.1 M

0.02 M

0.01 M

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