8\% of the voters in an election did not cast their votes. In this election, there were only two candidates. T

Question

8\% of the voters in an election did not cast their votes. In this election, there were only two candidates. The winner, by obtaining 48\% of the total votes, defeated his contestant by 110 votes . The total number of voters in the election was:

Accepted Answer

Let the total number of voters in the election be

x

.
* Voters who did not cast their votes =

8%

of

x

* Total casted votes =

100% - 8% = 92%

of

x

The winner received

48%

of the total votes.
Therefore, the votes received by the losing candidate will be the remaining casted votes:

Loser’s votes = 92% of x - 48% of x = 44% of x

The difference between the winner's and loser's votes is given as

110 votes

:

48% of x - 44% of x = 110

4% of x = 110

\frac{4}{100} \times x = 110

x = \frac{110 \times 100}{4}

x = 110 \times 25 = 2750

Thus, the total number of voters was

2750

.

$8%$ of the voters in an election did not cast their votes. In this election, there were only two candidates. The winner, by obtaining $48%$ of the total votes, defeated his contestant by $110 votes$ . The total number of voters in the election was:

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8% of the voters in an election did not cast their votes. In this election, there were only two candidates. The winner, by obtaining 48% of the total votes, defeated his contestant by 110 votes. The total number of voters in the election was: