A 20 litre container at 400 K contains CO_2(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO ). The volume of the containe - Chemistry MCQ NEET (UG) 2017 2026 | ExamTest.live

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A 20 litre container at 400 K contains CO_{2} (g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of CO_{2} attains its maximum value, will be:(Given that: SrCO_{3} (s) ⇌ SrO (s) + CO_{2} (g), K_{p} = 1.6 atm)

Solution & Step-by-step Explanation

For the equilibrium: SrCO_{3} (s) ⇌ SrO (s) + CO_{2} (g) The equilibrium constant is K_{p} = P_{CO_{2}} = 1.6 atm .Initially, V_{1} = 20 L and P_{1} = 0.4 atm .The pressure of CO_{2} will remain constant at 1.6 atm (the K_{p} value) as long as equilibrium is maintained by the solid decomposition.We can use Boyle's Law (P_{1} V_{1} = P_{2} V_{2}) because the moles of gas are determined by the initial amount until the equilibrium pressure is reached. 0.4 \times 20 = 1.6 \times V_{2} 8 = 1.6 \times V_{2} V_{2} = \frac{8}{1.6} = 5 L .

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A 20 litre container at 400 K contains CO_{2} (g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of CO_{2} attains its maximum value, will be:(Given that: SrCO_{3} (s) ⇌ SrO (s) + CO_{2} (g), K_{p} = 1.6 atm)

10 litre

4 litre

2 litre

5 litre

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