A 3 -digit number ABC , where A is at the hundredth place, B is at the tenth place and C is at the unit's place, is re-written as ABCABC and is divide - Quantitative Aptitude MCQ Competitive Exam 2026 | ExamTest.live

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A 3 -digit number A BC, where A is at the hundredth place, B is at the tenth place and C is at the unit's place, is re-written as A BC A BC and is divided by the LCM of 7, 11 and 13 . What will be the result?

Solution & Step-by-step Explanation

A 3 -digit number repeated twice to form a 6 -digit number can be written as: ABCABC = ABC \times 1001 Now let's find the LCM of the prime numbers 7, 11, and 13 : LCM (7, 11, 13) = 7 \times 11 \times 13 = 1001 According to the question, A BC A BC is divided by the LCM of 7, 11, and 13 : Result = \frac{ABCABC}{1001} = \frac{ABC \times 1001}{1001} = ABC

Try it yourself before checking the explanation above.

A 3 -digit number A BC, where A is at the hundredth place, B is at the tenth place and C is at the unit's place, is re-written as A BC A BC and is divided by the LCM of 7, 11 and 13 . What will be the result?

ABC

CBA

BCA

AAB

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