A, B and C can complete a piece of work in 3 days, 4 days and 6 days, respectively. They get Rs. 432 for completing the job. If A, B and C work together to complete the job, A’s share is:
- ARs. 108
- BRs. 144
- CRs. 72
- DRs. 192
Solution & Step-by-step Explanation
To find A's share, we divide the total wages according to the efficiency ratio of A, B, and C.
The time taken by A, B, and C to complete the work is 3 days, 4 days, and 6 days respectively.
Let the total work be the LCM of 3, 4, and 6, which is 12 units.
Efficiency of A=
3
12
=4 units/day
Efficiency of B=
4
12
=3 units/day
Efficiency of C=
6
12
=2 units/day
The ratio of their efficiencies is A:B:C=4:3:2.
Since they work together for the entire duration, the wages are shared in the ratio of their efficiencies.
Total ratio units = 4+3+2=9
A's share =
9
4
×432=4×48=Rs. 192
The time taken by A, B, and C to complete the work is 3 days, 4 days, and 6 days respectively.
Let the total work be the LCM of 3, 4, and 6, which is 12 units.
Efficiency of A=
3
12
=4 units/day
Efficiency of B=
4
12
=3 units/day
Efficiency of C=
6
12
=2 units/day
The ratio of their efficiencies is A:B:C=4:3:2.
Since they work together for the entire duration, the wages are shared in the ratio of their efficiencies.
Total ratio units = 4+3+2=9
A's share =
9
4
×432=4×48=Rs. 192