A, B, C, D, E, F, G and H are eight friends sitting around a circle, facing towards the centre. C is sitting second to the left of F. F is sitting between B and E. B is the neighbour of A. H is sitting to the immediate right of G. D is to the immediate left of G. What is the position of A?

Let's determine the positions step-by-step around the circular table (facing the center):
Place F at any position (say position 1).

C is sitting second to the left of F. Moving clockwise (left when facing inside), C is at position 7.

F is sitting between B and E. This leaves two possibilities for B and E (positions 2 and 8).

D is to the immediate left of G, and H is to the immediate right of G. This means D, G, H must be in consecutive order clockwise: D → G → H.

B is a neighbor of A.

Let's place them:

If F is at pos 1, C is at pos 7.

If E is at pos 8 and B is at pos 2:

Since B is a neighbor of A, A must be at pos 3.

The remaining three spots are 4, 5, 6.

We need to place D, G, H sequentially.

If D is at pos 4, G is at pos 5, and H is at pos 6.

Let's check the remaining conditions: H is to the immediate right of G (pos 6 is left of pos 5 when facing center? No, facing inside, clockwise is left, counter-clockwise is right. So from G at pos 5, immediate right is pos 4, immediate left is pos 6).

Let's use positions explicitly:
Let 1 to 8 be arranged counter-clockwise (1 is top, 2 is top-left, etc., where right is counter-clockwise and left is clockwise).

F =1

Left of F by 2 places (clockwise) → C =7

F is between B and E. Let's try B =2 (right of F) and E =8 (left of F).

B is a neighbor of A → A =3.

We have positions 4, 5, 6 empty.

D is to the immediate left of G. In counter-clockwise layout, left means clockwise. So G's left is G+1. Thus, if G =5, left is 6→ D =6.

H is to the immediate right of G. Right means counter-clockwise (G-1) → H =4.

Let's check if everything fits perfectly:

Circle: 1:F, 2:B, 3:A, 4:H, 5:G, 6:D, 7:C, 8:E.

Check: C(7) is second to the left of F(1)? Yes (1→8→7).

F(1) is between B(2) and E(8)? Yes.

B(2) is neighbor of A(3)? Yes.

D(6) is immediate left of G(5)? Yes.

H(4) is immediate right of G(5)? Yes.

Now let's check the position of A (at pos 3):

It is sitting between H (pos 4) and B (pos 2).

Let's check the given options:

Option A: To the immediate left of C (Immediate left of C(7) is 8(E)). Incorrect.

Option B: Between H and C. Incorrect.

Option C: To the immediate right of E. Incorrect.

Option D: Between D and B. Incorrect.

Let's re-verify the other case where B and E are swapped:

F =1, C =7.

Let B =8 and E =2.

B is a neighbor of A → A =9≡1 (Not possible, F is at 1). So A must be at 7? But C is at 7. Thus, this configuration is invalid.

Let's look at option A again: "To the immediate left of C". If A is next to C, let's see how:
What if the circle positions are:

F =1, C =7.

If E =2, B =8, then A =9 is blocked by F.
What if C is second to the left of F means clockwise shift? Let's trace positions linearly:
C _ F
If F is 3, C is 1.
F is between B and E → either B=2, E=4 or E=2, B=4.
Case A: B=2, E=4. B is neighbor of A → A must be 8 (if circle size 8, 1's left neighbor is 8).
Let's check: 1:C, 2:B, 3:F, 4:E.
If A =8, then remaining are 5, 6, 7.
D is immediate left of G, H is immediate right of G → D, G, H must be contiguous.
If G=6, immediate left (increasing index) is 7 → D=7. Immediate right (decreasing index) is 5 → H=5.
Let's check the full layout: 1:C, 2:B, 3:F, 4:E, 5:H, 6:G, 7:D, 8:A.
Let's check position of A (8): It is between D (7) and C (1).
Also, A is to the immediate left of C (since moving from 8 to 1 is to the left/clockwise if 1 is right of 8).
Let's double-check: position of A is 8, position of C is 1. Immediate left of C is 8. This matches Option A perfectly!