A ball of mass 0.15 kg is dropped from a height 10 m , strikes the ground and rebounds to the same height. The magnitude of impulse imparted to the ba - Physics MCQ NEET 2021 2026 | ExamTest.live

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A ball of mass 0.15 kg is dropped from a height 10 m, strikes the ground and rebounds to the same height. The magnitude of impulse imparted to the ball is (g = 10 m/s^{2}) nearly:

Solution & Step-by-step Explanation

Velocity just before striking v = 2 g h = 2 \times 10 \times 10 = 200 = 102 m/s (downwards).Since it rebounds to the same height, velocity just after rebound v^{'} = 102 m/s (upwards).Impulse = Change in momentum = m [v^{'} - (- v)] = 2 m v $ Impulse = 2 \times 0.15 \times 102 = 0.3 \times 14.14 \approx 4.24 kg m/s $

Try it yourself before checking the explanation above.

A ball of mass 0.15 kg is dropped from a height 10 m, strikes the ground and rebounds to the same height. The magnitude of impulse imparted to the ball is (g = 10 m/s^{2}) nearly:

21 kg m/s

1.4 kg m/s

0 kg m/s

4.2 kg m/s

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