A boat is moving due east in a region where the earth's magnetic field is 5.0 × 10^-5 NA^-1m^-1 due north and horizontal. The boat carries a vertical - Physics MCQ FIITJEE AIEEE 2011 (Set Q) 2026 | ExamTest.live

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A boat is moving due east in a region where the earth's magnetic field is 5.0 \times 1 0^{- 5} NA^{- 1} m^{- 1} due north and horizontal. The boat carries a vertical aerial 2 m long. If the speed of the boat is 1.50 ms^{- 1}, the magnitude of the induced emf in the wire of aerial is:

Solution & Step-by-step Explanation

Induced emf (e) in a moving conductor is given by: e = B v l where B, v, and l are mutually perpendicular.Here, B = 5.0 \times 1 0^{- 5} T (North), v = 1.50 m/s (East), and l = 2 m (Vertical). e = (5.0 \times 1 0^{- 5}) \times 1.50 \times 2 e = 15 \times 1 0^{- 5} V = 0.15 \times 1 0^{- 3} V = 0.15 mV

Try it yourself before checking the explanation above.

A boat is moving due east in a region where the earth's magnetic field is 5.0 \times 1 0^{- 5} NA^{- 1} m^{- 1} due north and horizontal. The boat carries a vertical aerial 2 m long. If the speed of the boat is 1.50 ms^{- 1}, the magnitude of the induced emf in the wire of aerial is:

0.75 mV

0.50 mV

0.15 mV

1 mV

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