A body covers half the distance with a speed of $10\text{m/s}$ and the remaining half with a speed of $40\text{m/s}$. Then the average speed of the body over the entire journey

When an object covers two equal halves of a total distance with two different uniform speeds $v_1$ and $v_2$, the average speed ($v_{\text{avg}}$) over the entire trip is calculated using the harmonic mean formula:
$$v_{\text{avg}}=\frac{2v_1{v}_2}{v_1+v_2}$$

Given parameters:

* $v_1=10\text{m/s}$
* $v_2=40\text{m/s}$

Substituting these values into the equation:

$$v_{\text{avg}}=\frac{2\times 10\times 40}{10+40}$$

$$v_{\text{avg}}=\frac{800}{50}=16\text{m/s}$$