A body is executing simple harmonic motion with frequency n , the frequency of its potential energy is: - Physics MCQ NEET 2021 2026 | ExamTest.live | ExamTest.live

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A body is executing simple harmonic motion with frequency n, the frequency of its potential energy is:

A $3 n$
B $4 n$
C $n$
D $2 n$

Solution & Step-by-step Explanation

Displacement x = A sin (ω t) = A sin (2 πn t) .Potential Energy PE = \frac{1}{2} k x^{2} = \frac{1}{2} k A^{2} sin^{2} (2 πn t) .Using sin^{2} θ = \frac{1 - c o s 2 θ}{2} : PE = \frac{1}{2} k A^{2} (\frac{1 - cos ( 4 πn t )}{2}) The frequency of the cos term is 2 n .

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A body is executing simple harmonic motion with frequency n, the frequency of its potential energy is:

A

3 n

B

4 n

C

n

D

2 n

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