A body is initially moving with a velocity of 15m/s. It undergoes an acceleration of 4m/s
2
for 6 seconds. Find the displacement (in m) of this body in these 6 seconds.

Given data:
Initial velocity (u) = 15m/s

Acceleration (a) = 4m/s
2


Time (t) = 6s

Using the second equation of motion:

s=ut+
2
1
​
at
2

Substitute the given values:

s=(15×6)+
2
1
​
×4×(6)
2

s=90+2×36
s=90+72=162m
Hence, the displacement of the body is 162m.