A body of mass m , accelerates uniformly from rest to v_1 in time t_1 . The instantaneous power delivered to the body as a function of time t is: - Physics MCQ AIEEE 2004 2026 | ExamTest.live

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A body of mass m, accelerates uniformly from rest to v_{1} in time t_{1} . The instantaneous power delivered to the body as a function of time t is:

Solution & Step-by-step Explanation

Uniform acceleration a = \frac{v _{1} - 0}{t _{1}} = \frac{v _{1}}{t _{1}} .Velocity as a function of time t : v (t) = u + a t = 0 + (\frac{v _{1}}{t _{1}}) t .Force acting on the body: F = ma = m (\frac{v _{1}}{t _{1}}) .Instantaneous power P = F \cdot v : P = (m \frac{v _{1}}{t _{1}}) (\frac{v _{1}}{t _{1}} t) P = \frac{m v _{1}^{2} t}{t _{1}^{2}}

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A body of mass m, accelerates uniformly from rest to v_{1} in time t_{1} . The instantaneous power delivered to the body as a function of time t is:

\frac{m v _{1} t}{t _{1}}

\frac{m v _{1}^{2} t}{t _{1}^{2}}

\frac{m v _{1} t ^{2}}{t _{1}}

\frac{m v _{1}^{2} t}{t _{1}}

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