A body weighs 72 N on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of the earth? - Physics MCQ NEET 2020 E1 2026 | ExamTest.live

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A body weighs 72 N on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of the earth?

Solution & Step-by-step Explanation

Weight at height h is W_{h} = \frac{W _{0}}{( 1 + h / R ) ^{2}} .Given W_{0} = 72 N and h = R /2 . W_{h} = \frac{72}{( 1 + 1/2 ) ^{2}} = \frac{72}{( 3/2 ) ^{2}} = \frac{72}{9/4} W_{h} = \frac{72 \times 4}{9} = 8 \times 4 = 32 N

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A body weighs 72 N on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of the earth?

48 N

32 N

30 N

24 N

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