A boy can throw a stone up to a maximum height of 10 m . The maximum horizontal distance that the boy can throw the same stone up to will be: - Physics MCQ AIEEE 2012 2026 | ExamTest.live

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A boy can throw a stone up to a maximum height of 10 m . The maximum horizontal distance that the boy can throw the same stone up to will be:

Solution & Step-by-step Explanation

Maximum vertical height H_{m a x} = \frac{u ^{2}}{2 g} .Given H_{m a x} = 10 m, so \frac{u ^{2}}{2 g} = 10 ⟹ \frac{u ^{2}}{g} = 20 .Maximum horizontal range R_{m a x} occurs at an angle of 4 5^{\circ} : R_{m a x} = \frac{u ^{2} s i n ( 9 0 ^{\circ} )}{g} = \frac{u ^{2}}{g} .Substituting \frac{u ^{2}}{g} = 20, we get R_{m a x} = 20 m .

Try it yourself before checking the explanation above.

A boy can throw a stone up to a maximum height of 10 m . The maximum horizontal distance that the boy can throw the same stone up to will be:

20\sqrt{2} , \text{m}

10 , \text{m}

10\sqrt{2} , \text{m}

20 , \text{m}

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