A boy recorded the weight of some of his friends as $32\text{kg}$, $30\text{kg}$, $40\text{kg}$, $65\text{kg}$, $54\text{kg}$, $38\text{kg}$, $36\text{kg}$, $45\text{kg}$, $50\text{kg}$, $52\text{kg}$, $40\text{kg}$. What is the median?

First, let's arrange the weights in ascending order:
$30,32,36,38,40,40,45,50,52,54,65$

Count the number of observations ($N$):

$$N=11\text{ (which is an odd number)}$$

The median for an odd number of observations is the ${\left(\frac{N+1}{2}\right)}^{\text{th}}$ term:

$$\text{Median}={\left(\frac{11+1}{2}\right)}^{\text{th}}\text{ term}=6^{\text{th}}\text{ term}$$

The $6^{\text{th}}$ term in our sorted sequence is $40$.
Therefore, the median is $40\text{kg}$.