A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm . How much further it will penetrate before coming to rest assumi - Physics MCQ AIEEE 2026 | ExamTest.live

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A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm . How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?

Solution & Step-by-step Explanation

Let the initial velocity be v and resistance force be F .Case 1: v \to v /2 over s_{1} = 3 cm .Using v^{2} - u^{2} = 2 a s : (v /2)^{2} - v^{2} = 2 a (3) - 3 v^{2} /4 = 6 a ⟹ a = - v^{2} /8 Case 2: v /2 \to 0 over s_{2} . 0^{2} - (v /2)^{2} = 2 a s_{2} - v^{2} /4 = 2 (- v^{2} /8) s_{2} - v^{2} /4 = (- v^{2} /4) s_{2} ⟹ s_{2} = 1 cm

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A bullet fired into a fixed target loses half of its velocity after penetrating 3 cm . How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?

3.0 cm

2.0 cm

1.5 cm

1.0 cm

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