A bullet is fired from a gun at the speed of 280 m s^-1 in the direction 30^ above the horizontal. The maximum height attained by the bullet is ( g = - Physics MCQ NEET 2023 2026 | ExamTest.live

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A bullet is fired from a gun at the speed of 280 m s^{- 1} in the direction 3 0^{\circ} above the horizontal. The maximum height attained by the bullet is (g = 9.8 m s^{- 2}, sin 3 0^{\circ} = 0.5):

Solution & Step-by-step Explanation

The maximum height H reached by a projectile is given by: H = \frac{u ^{2} sin ^{2} θ}{2 g} Given: u = 280 m/s θ = 3 0^{\circ} g = 9.8 m/s^{2} $ H = \frac{( 280 ) ^{2} \times ( s i n 3 0 ^{\circ} ) ^{2}}{2 \times 9.8} $ H = \frac{78400 \times ( 0.5 ) ^{2}}{19.6} H = \frac{78400 \times 0.25}{19.6} = \frac{19600}{19.6} = 1000 m

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A bullet is fired from a gun at the speed of 280 m s^{- 1} in the direction 3 0^{\circ} above the horizontal. The maximum height attained by the bullet is (g = 9.8 m s^{- 2}, sin 3 0^{\circ} = 0.5):

2800 m

2000 m

1000 m

3000 m

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