A can complete a work in 18 days. If B is only 90\% efficient as compared to A, then in how many days will B alone complete the same work? - Quantitative Aptitude MCQ SSC Selection Post 2021 Matriculation Level 2026 | ExamTest.live

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A can complete a work in 18 days. If B is only 90% efficient as compared to A, then in how many days will B alone complete the same work?

Solution & Step-by-step Explanation

Let the efficiency of A be 10 units/day.Since B is 90% efficient compared to A: Efficiency of B = \frac{90}{100} \times 10 = 9 units/day Total Work = Efficiency of A \times Days taken by A = 10 \times 18 = 180 units The time taken by B alone to complete the same work is: Days taken by B = \frac{Total Work}{Efficiency of B} = \frac{180}{9} = 20 days

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A can complete a work in 18 days. If B is only 90% efficient as compared to A, then in how many days will B alone complete the same work?

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