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A capacitor is charged by a battery. The battery is removed and another identical uncharged capacitor is connected in parallel. The total electrostatic energy of the resulting system:

  1. A
    Decreases by a factor of
  2. B
    Remains the same
  3. C
    Increases by a factor of
  4. D
    Increases by a factor of

Solution & Step-by-step Explanation

Initial energy stored in the first capacitor: .When it is connected to an identical uncharged capacitor in parallel, the charge is shared equally ( each).Total final energy:

Comparing and :

The energy decreases by a factor of .

Practice this question

Try it yourself before checking the explanation above.

A capacitor is charged by a battery. The battery is removed and another identical uncharged capacitor is connected in parallel. The total electrostatic energy of the resulting system:
A
Decreases by a factor of
B
Remains the same
C
Increases by a factor of
D
Increases by a factor of

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Electrostatic Potential and CapacitanceEnergy Stored in Capacitor

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