A capacitor of capacitance C is connected across an AC source of voltage V , given by V = V_0 ω t . The displacement current between the plates of the - Physics MCQ NEET 2021 2026 | ExamTest.live

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A capacitor of capacitance C is connected across an AC source of voltage V, given by V = V_{0} sin ω t . The displacement current between the plates of the capacitor, would then be given by:

Solution & Step-by-step Explanation

The displacement current I_{d} is equal to the conduction current I_{c} .The charge on the capacitor is q = C V = C V_{0} sin ω t .The conduction current I_{c} is given by: I_{c} = \frac{d q}{d t} = \frac{d}{d t} (C V_{0} sin ω t) I_{c} = C V_{0} ω cos ω t Since I_{d} = I_{c}, we have: I_{d} = V_{0} C ω cos ω t

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A capacitor of capacitance C is connected across an AC source of voltage V, given by V = V_{0} sin ω t . The displacement current between the plates of the capacitor, would then be given by:

I_{d} = ω V_{0} C sin ω t

I_{d} = V_{0} C ω sin ω t

I_{d} = V_{0} C ω cos ω t

I_{d} = \frac{V _{0}}{ω C} sin ω t

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