A car covers the first 80km of its journey at a speed of 40km/h. The driver makes a stop at the tea-stall for 30 minutes and then continues his journey at a speed of 60km/h for 4 hours. What is his average speed (in km/h, correct to 1 decimal place)?
- A49.2
- B48.5
- C55.4
- D53.3
Solution & Step-by-step Explanation
To find the average speed, we use the formula:
Average Speed=
Total Time
Total Distance
First part of the journey:
Distance
1
=80km
Speed
1
=40km/h
Time
1
=
40
80
=2hours
Stoppage time:
Time
stop
=30minutes=
60
30
=0.5hours
Second part of the journey:
Speed
2
=60km/h
Time
2
=4hours
Distance
2
=Speed
2
×Time
2
=60×4=240km
Total Calculation:
Total Distance=80+240=320km
Total Time=2+0.5+4=6.5hours
Average Speed=
6.5
320
=
65
3200
≈49.23km/h
Rounding to one decimal place, we get 49.2km/h.
Average Speed=
Total Time
Total Distance
First part of the journey:
Distance
1
=80km
Speed
1
=40km/h
Time
1
=
40
80
=2hours
Stoppage time:
Time
stop
=30minutes=
60
30
=0.5hours
Second part of the journey:
Speed
2
=60km/h
Time
2
=4hours
Distance
2
=Speed
2
×Time
2
=60×4=240km
Total Calculation:
Total Distance=80+240=320km
Total Time=2+0.5+4=6.5hours
Average Speed=
6.5
320
=
65
3200
≈49.23km/h
Rounding to one decimal place, we get 49.2km/h.