A car starts from rest and accelerates at 5 m/s^2 . At t = 4 s , a ball is dropped out of a window by a person

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A car starts from rest and accelerates at 5 m/s^2 . At t = 4 s , a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at t = 6 s ? ( g = 10 m/s^2 )

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![image](https://pub-7faa453bd1ec4bf0a04cc031c6f058de.r2.dev/images/ed91cc73-4421-48a6-9737-c3f5143cbbce.png) At t = 4 s , the velocity of the car v = u + at = 0 + 5(4) = 20 m/s .When the ball is dropped, it retains the horizontal velocity v_x = 20 m/s .The ball is in free fall for 2 s ( t=6 - t=4 ).Vertical velocity v_y = g t' = 10(2) = 20 m/s .Net velocity V = √(v_x^2 + v_y^2) = √(20^2 + 20^2) = 20√(2) m/s .Once dropped, the only acceleration is gravity g = 10 m/s^2 .

A car starts from rest and accelerates at $5 m/s^{2}$ . At $t = 4 s$ , a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at $t = 6 s$ ? ( $g = 10 m/s^{2}$ )

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A car starts from rest and accelerates at 5m/s2. At t=4s, a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at t=6s? (g=10m/s2)