A Carnot engine has an efficiency of 50\% when its source is at a temperature 327^ . The temperature of the sink is: - Physics MCQ NEET 2023 2026 | ExamTest.live

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A Carnot engine has an efficiency of 50% when its source is at a temperature 32 7^{\circ} C . The temperature of the sink is:

Solution & Step-by-step Explanation

ShutterstockThe efficiency η of a Carnot engine is given by: η = 1 - \frac{T _{s ink}}{T _{so u rce}} Given: η = 50% = 0.5 T_{so u rce} = 32 7^{\circ} C = 327 + 273 = 600 K Substituting the values: 0.5 = 1 - \frac{T _{s ink}}{600} \frac{T _{s ink}}{600} = 1 - 0.5 = 0.5 T_{s ink} = 600 \times 0.5 = 300 K Converting back to Celsius: T_{s ink} = 300 - 273 = 2 7^{\circ} C

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A Carnot engine has an efficiency of 50% when its source is at a temperature 32 7^{\circ} C . The temperature of the sink is:

2 7^{\circ} C

1 5^{\circ} C

10 0^{\circ} C

20 0^{\circ} C

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