A charged particle of mass m and charge q travels on a circular path of radius r that is perpendicular to a magnetic field B . The time taken by the p - Physics MCQ AIEEE 2026 | ExamTest.live

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A charged particle of mass m and charge q travels on a circular path of radius r that is perpendicular to a magnetic field B . The time taken by the particle to complete one revolution is:

Solution & Step-by-step Explanation

For circular motion in a magnetic field: \frac{m v ^{2}}{r} = q v B ⟹ v = \frac{qB r}{m} .Time period T = \frac{2 π r}{v} : T = \frac{2 π r}{\frac{qB r}{m}} = \frac{2 πm}{qB}

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A charged particle of mass m and charge q travels on a circular path of radius r that is perpendicular to a magnetic field B . The time taken by the particle to complete one revolution is:

2 πm q / B

2 π^{2} qB / m

2 π qB / m

2 πm / qB

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