A circus tent is cylindrical to a height of $3\text{ m}$ and conical above it. If the radius of the base is $50\text{ m}$ and the slant height of the cone is $52\text{ m}$, then the total area of the canvas required to make it is:

The total area of canvas required is equal to the curved surface area (CSA) of the cylindrical part plus the curved surface area (CSA) of the conical part.Given:Radius of the base, $r=50\text{ m}$ Height of the cylinder, $h=3\text{ m}$ Slant height of the cone, $l=52\text{ m}$ $
$\text{CSA of Cylinder}=2\pi rh=2\times \pi \times 50\times 3=300\pi {\text{ m}}^2$ $
$$\text{CSA of Cone}=\pi rl=\pi \times 50\times 52=2600\pi {\text{ m}}^2$$
$$\text{Total Area of Canvas}=300\pi +2600\pi =2900\pi {\text{ m}}^2$$