A city's population grows by 10% in the first year, 20% in the second year and 10% in the third year. If the population after 3 years is 8,71,200, then what was the original population 3 years ago?
- A7,00,000
- B7,92,000
- C6,60,000
- D6,00,000
Solution & Step-by-step Explanation
Let the original population 3 years ago be P.
The population grows successively by 10%, 20%, and 10% over three years.
Final Population=P×(1+
100
10
)×(1+
100
20
)×(1+
100
10
)
871200=P×
100
110
×
100
120
×
100
110
871200=P×
10
11
×
5
6
×
10
11
871200=P×
500
726
P=
726
871200×500
Let's divide 871200 by 726:
726
871200
=1200
P=1200×500=6,00,000
The population grows successively by 10%, 20%, and 10% over three years.
Final Population=P×(1+
100
10
)×(1+
100
20
)×(1+
100
10
)
871200=P×
100
110
×
100
120
×
100
110
871200=P×
10
11
×
5
6
×
10
11
871200=P×
500
726
P=
726
871200×500
Let's divide 871200 by 726:
726
871200
=1200
P=1200×500=6,00,000