HomeTestsSearchRankProfile
mediumMCQCompetitive Exam2026Quantitative Aptitude
1 mark

A city's population grows by 10% in the first year, 20% in the second year and 10% in the third year. If the population after 3 years is 8,71,200, then what was the original population 3 years ago?

  1. A
    7,00,000
  2. B
    7,92,000
  3. C
    6,60,000
  4. D
    6,00,000

Solution & Step-by-step Explanation

Let the original population 3 years ago be P.
The population grows successively by 10%, 20%, and 10% over three years.

Final Population=P×(1+
100
10

)×(1+
100
20

)×(1+
100
10

)
871200=P×
100
110

×
100
120

×
100
110


871200=P×
10
11

×
5
6

×
10
11


871200=P×
500
726


P=
726
871200×500


Let's divide 871200 by 726:

726
871200

=1200
P=1200×500=6,00,000

Practice this question

Try it yourself before checking the explanation above.

A city's population grows by 10% in the first year, 20% in the second year and 10% in the third year. If the population after 3 years is 8,71,200, then what was the original population 3 years ago?
A
7,00,000
B
7,92,000
C
6,60,000
D
6,00,000

Share This Question

Related Questions

Ready for a Full Test?

Practice with timed mock tests and track your performance across Quantitative Aptitude.

Discussion