A coin is tossed twice. If E and F denote the occurrence of a head on the first toss and second toss respectively, then what is P(E F) equal to? - Mathematics MCQ Mathematics Mock Test - 4 2026 | ExamTest.live

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A coin is tossed twice. If E and F denote the occurrence of a head on the first toss and second toss respectively, then what is P (E \cup F) equal to?

Solution & Step-by-step Explanation

The sample space S = {HH, H T, T H, TT}, so n (S) = 4 .Event E (Head on 1st toss) = {HH, H T}, so P (E) = 2/4 = 1/2 .Event F (Head on 2nd toss) = {HH, T H}, so P (F) = 2/4 = 1/2 .Event E \cap F (Head on both) = {HH}, so P (E \cap F) = 1/4 .Using the addition theorem: P (E \cup F) = P (E) + P (F) - P (E \cap F) P (E \cup F) = \frac{1}{2} + \frac{1}{2} - \frac{1}{4} = 1 - \frac{1}{4} = \frac{3}{4}

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A coin is tossed twice. If E and F denote the occurrence of a head on the first toss and second toss respectively, then what is P (E \cup F) equal to?

1/4

1/2

3/4

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