A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is:
- AC
2
A
3
- BC
3
A
2
- CC
3
A
4
- DC
4
A
3
Solution & Step-by-step Explanation
In an hcp lattice, the number of atoms per unit cell (N) is 6.
Number of octahedral voids is equal to the number of atoms in the lattice (N=6).
Number of anions (A) =6.
Number of cations (C) =75% of octahedral voids =0.75×6=4.5.
Ratio C:A=4.5:6=9:12=3:4.
Formula: C
3
A
4
.
Number of octahedral voids is equal to the number of atoms in the lattice (N=6).
Number of anions (A) =6.
Number of cations (C) =75% of octahedral voids =0.75×6=4.5.
Ratio C:A=4.5:6=9:12=3:4.
Formula: C
3
A
4
.