A compound X contains 32\% of A, 20\% of B, and the remaining percentage of C. The empirical formula of X is:(Given atomic masses: A = 64 , B = 40 , C - Chemistry MCQ NEET (UG) 2024 2026 | ExamTest.live

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A compound X contains 32% of A, 20% of B, and the remaining percentage of C. The empirical formula of X is:(Given atomic masses: A = 64, B = 40, C = 32)

Solution & Step-by-step Explanation

1. Percentage of C = 100 - (32 + 20) = 48% .2. Calculate relative number of moles:Moles of A: \frac{32}{64} = 0.5 Moles of B: \frac{20}{40} = 0.5 Moles of C: \frac{48}{32} = 1.5 Simplest ratio (divide by 0.5):A: \frac{0.5}{0.5} = 1 B: \frac{0.5}{0.5} = 1 C: \frac{1.5}{0.5} = 3 Formula: ABC_{3} .

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A compound X contains 32% of A, 20% of B, and the remaining percentage of C. The empirical formula of X is:(Given atomic masses: A = 64, B = 40, C = 32)

ABC_{3}

AB_{2} C_{2}

ABC_{4}

A_{2} BC_{2}

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