A cycle wheel of radius 0.5 m is rotated with a constant angular velocity of 10 rad/s in a region of a magnetic field of 0.1 T which is perpendicular - PHYSICS MCQ NEET 2019 2026 | ExamTest.live

mediumMCQNEET 20192026PHYSICS

1 mark

A cycle wheel of radius 0.5 m is rotated with a constant angular velocity of 10 rad/s in a region of a magnetic field of 0.1 T which is perpendicular to the plane of the wheel. The EMF generated between its centre and the rim is:

Solution & Step-by-step Explanation

The EMF generated between the center and the rim of a rotating disc (or wheel spokes) is given by: e = \frac{1}{2} B ω R^{2} e = \frac{1}{2} \times 0.1 \times 10 \times (0.5)^{2} e = 0.5 \times 0.25 = 0.125 V .

Try it yourself before checking the explanation above.

A cycle wheel of radius 0.5 m is rotated with a constant angular velocity of 10 rad/s in a region of a magnetic field of 0.1 T which is perpendicular to the plane of the wheel. The EMF generated between its centre and the rim is:

0.25 V

0.125 V

0.5 V

zero

Practice with timed mock tests and track your performance across PHYSICS.