A cylindrical tube, open at both ends, has a fundamental frequency, f , in air. The tube is dipped vertically in water so that half of it is in water. - Physics MCQ AIEEE 2012 2026 | ExamTest.live

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A cylindrical tube, open at both ends, has a fundamental frequency, f, in air. The tube is dipped vertically in water so that half of it is in water. The fundamental frequency of the air-column is now:

Solution & Step-by-step Explanation

For an open tube of length L, the fundamental frequency is f = \frac{v}{2 L} .When the tube is dipped half in water, the bottom becomes closed. The length of the air column is now L^{'} = \frac{L}{2} .The fundamental frequency of a closed tube is f^{'} = \frac{v}{4 L ^{'}} .Substituting L^{'} = \frac{L}{2} : f^{'} = \frac{v}{4 ( L /2 )} = \frac{v}{2 L} = f

Try it yourself before checking the explanation above.

A cylindrical tube, open at both ends, has a fundamental frequency, f, in air. The tube is dipped vertically in water so that half of it is in water. The fundamental frequency of the air-column is now:

f

\frac{f}{2}

\frac{3f}{4}

2f

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