A dealer marks an article 40% above its cost price, and sells it by giving two successive discounts of 15% and 25% on the marked price. If he suffers a loss of Rs. 43, then the marked price (in Rs.) of the article is:
- A560
- B700
- C420
- D480
Solution & Step-by-step Explanation
Let the cost price (CP) be 100x.
Marked Price (MP) = 100x×1.40=140x.
Two successive discounts of 15% and 25% are given on MP:
Selling Price (SP)=140x×(1−
100
15
)×(1−
100
25
)
SP=140x×
20
17
×
4
3
=140x×
80
51
=1.75x×51=89.25x
Loss = CP−SP=100x−89.25x=10.75x.
Given loss = Rs. 43:
10.75x=43⟹x=
10.75
43
=4
Thus, Marked Price (MP) = 140x=140×4=Rs. 560.
Marked Price (MP) = 100x×1.40=140x.
Two successive discounts of 15% and 25% are given on MP:
Selling Price (SP)=140x×(1−
100
15
)×(1−
100
25
)
SP=140x×
20
17
×
4
3
=140x×
80
51
=1.75x×51=89.25x
Loss = CP−SP=100x−89.25x=10.75x.
Given loss = Rs. 43:
10.75x=43⟹x=
10.75
43
=4
Thus, Marked Price (MP) = 140x=140×4=Rs. 560.