A dice has numbers 2, 3, 5, 6, 7 and 8 on its sides. Two different positions of the same dice are shown. In the first position, the visible faces are 7, 3, and 5. In the second position, the visible faces are 7, 2, and 6. Select the number that will be on the face opposite to the one having 8.

To find the face opposite to 8, let's analyze the two given positions of the dice:Position 1 visible faces: 7, 3, 5Position 2 visible faces: 7, 2, 6Since the number 7 is common to both positions, we can list the remaining numbers by moving in a clockwise direction starting from 7:From Position 1: $7\to 3\to 5$ From Position 2: $7\to 2\to 6$ By matching the corresponding positions in the clockwise sequences:3 is opposite to 25 is opposite to 6The only remaining face on the dice is 8, which must be opposite to the common face, 7.