A die is thrown. Let A be the event that the number obtained is greater than 3 . Let B be the event that the number obtained is less than 5 . Then P(A - Mathematics MCQ AIEEE 2026 | ExamTest.live

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A die is thrown. Let A be the event that the number obtained is greater than 3 . Let B be the event that the number obtained is less than 5 . Then P (A \cup B) is:

Solution & Step-by-step Explanation

Sample space S = {1, 2, 3, 4, 5, 6} .Event A (number > 3): A = {4, 5, 6} .Event B (number < 5): B = {1, 2, 3, 4} .The union of events A and B : A \cup B = {1, 2, 3, 4, 5, 6} .Since A \cup B = S, the probability is: P (A \cup B) = \frac{n ( A \cup B )}{n ( S )} = \frac{6}{6} = 1

Try it yourself before checking the explanation above.

A die is thrown. Let A be the event that the number obtained is greater than 3 . Let B be the event that the number obtained is less than 5 . Then P (A \cup B) is:

\frac{3}{5}

0

1

\frac{2}{5}

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