A few students went on a trip and the total amount planned to be spent was $\text{₹ }96$. However, $4$ students did not turn up and as a result the remaining students had to contribute $\text{₹ }4$ extra. The number of students who attended the trip was:

Let the total initial number of planned students be $x$.
The total budget for the trip is $\text{₹ }96$.
The original planned contribution per student would be $\frac{96}{x}$.

Since $4$ students did not turn up, the actual number of students who attended the trip is $(x-4)$.
The new contribution per student becomes $\frac{96}{x-4}$.

According to the question, the contribution increased by $\text{₹ }4$:

$$\frac{96}{x-4}-\frac{96}{x}=4$$

Divide the entire equation by $4$:

$$\frac{24}{x-4}-\frac{24}{x}=1$$

Combine the fractions:

$$24\left(\frac{x-(x-4)}{x(x-4)}\right)=1$$

$$24\times \frac{4}{x^2-4x}=1$$

$$x^2-4x=96$$

$$x^2-4x-96=0$$

Factorize the quadratic equation:

$$(x-12)(x+8)=0$$

Since the number of students cannot be negative, we have $x=12$.

The question asks for the number of students who actually attended the trip:

$$\text{Students attended}=x-4=12-4=8$$