A few students went on a trip and the total amount planned to be spent was $\text{₹}96$. However, $4$ students did not turn up and as a result the remaining students had to contribute $\text{₹}4$ extra. The number of students who attended the trip was:

Let the initial number of students planned for the trip be $x$.
The total budget is $\text{₹}96$. So, the planned initial contribution per student was:

$$\text{Initial share}=\frac{96}{x}$$

Since $4$ students did not turn up, the number of students who actually attended the trip is $(x-4)$.
The new contribution per student becomes:

$$\text{New share}=\frac{96}{x-4}$$

According to the question, the difference between the new share and the initial share is $\text{₹}4$:

$$\frac{96}{x-4}-\frac{96}{x}=4$$

Divide the entire equation by $4$:

$$\frac{24}{x-4}-\frac{24}{x}=1$$

Let's find a common denominator:

$$24x-24(x-4)=x(x-4)$$

$$24x-24x+96=x^2-4x$$

$$x^2-4x-96=0$$

Solve this quadratic equation by splitting the middle term:

$$x^2-12x+8x-96=0$$

$$x(x-12)+8(x-12)=0$$

$$(x-12)(x+8)=0$$

Since the number of students cannot be negative, we have $x=12$.
The question asks for the number of students who attended the trip:

$$\text{Students who attended}=x-4=12-4=8$$