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A force F acting on an object varies with distance x as shown here. The force is in N and x is in m. The work done by the force in moving the object from x = 0 to x = 6 m is :

  1. A
    10.5 J
  2. B
    13.5 J
  3. C
    8.5 J
  4. D
    6.5 J

Solution & Step-by-step Explanation

The work done by a variable force F(x) in moving an object from x = a to x = b is given by the integral of F(x) with respect to x from a to b. Without the explicit function F(x) but given a graph, we can approximate the work done by treating the area under the F(x) curve as a combination of simple geometric shapes (rectangles, triangles) and calculating the area of each shape. The graph of F vs. x shows a trapezoidal shape from x = 0 to x = 6. The area under this curve (and thus the work done) can be approximated by breaking it down into simpler shapes or using the formula for the area of a trapezoid. The exact calculation depends on the specific details of the graph, which are not provided. However, the general approach involves integrating the force over the distance or approximating the area under the curve.

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A force F acting on an object varies with distance x as shown here. The force is in N and x is in m. The work done by the force in moving the object from x = 0 to x = 6 m is :
A
10.5 J
B
13.5 J
C
8.5 J
D
6.5 J

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