A force F = (5i + 3j + 2k) N is applied over a particle which displaces it from its origin to the point r = (2i - j) m . The work done on the particle - Physics MCQ AIEEE 2004 2026 | ExamTest.live

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A force F = (5 \hat{i} + 3 \hat{j} + 2 \hat{k}) N is applied over a particle which displaces it from its origin to the point r = (2 \hat{i} - \hat{j}) m . The work done on the particle in joules is:

Solution & Step-by-step Explanation

Work done is the dot product of force and displacement. W = F \cdot d Given F = 5 \hat{i} + 3 \hat{j} + 2 \hat{k} and displacement d = r_{f ina l} - r_{ini t ia l} = (2 \hat{i} - \hat{j} + 0 \hat{k}) - (0) = 2 \hat{i} - \hat{j} . W = (5 \hat{i} + 3 \hat{j} + 2 \hat{k}) \cdot (2 \hat{i} - \hat{j} + 0 \hat{k}) W = (5) (2) + (3) (- 1) + (2) (0) W = 10 - 3 = 7 J

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A force F = (5 \hat{i} + 3 \hat{j} + 2 \hat{k}) N is applied over a particle which displaces it from its origin to the point r = (2 \hat{i} - \hat{j}) m . The work done on the particle in joules is:

- 7

+ 7

+ 10

+ 13

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