A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio C_P/C_V of the mixture is: - Physics MCQ AIEEE 2026 | ExamTest.live

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A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio C_{P} / C_{V} of the mixture is:

Solution & Step-by-step Explanation

Helium (Monoatomic): n_{1} = 16/4 = 4 moles. C_{V 1} = \frac{3}{2} R .Oxygen (Diatomic): n_{2} = 16/32 = 0.5 moles. C_{V 2} = \frac{5}{2} R .For mixture: C_{V, mi x} = \frac{n _{1} C _{V 1} + n _{2} C _{V 2}}{n _{1} + n _{2}} = \frac{4 ( \frac{3}{2} R ) + 0.5 ( \frac{5}{2} R )}{4.5} = \frac{6 R + 1.25 R}{4.5} = \frac{7.25 R}{4.5} \approx 1.611 R C_{P, mi x} = C_{V, mi x} + R \approx 2.611 R .Ratio γ = \frac{2.611}{1.611} \approx 1.62 .

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A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio C_{P} / C_{V} of the mixture is:

1.59

1.62

1.4

1.54

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