A gene locus has two alleles A, a . If the frequency of dominant allele A is 0.4 , then what will be the frequency of homozygous dominant, heterozygou - Biology MCQ NEET 2019 2026 | ExamTest.live

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A gene locus has two alleles A, a . If the frequency of dominant allele A is 0.4, then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population?

Solution & Step-by-step Explanation

According to Hardy-Weinberg equilibrium: p + q = 1 and p^{2} + 2 pq + q^{2} = 1 .Given p (frequency of A) = 0.4 .Then q (frequency of a) = 1 - 0.4 = 0.6 .Frequency of homozygous dominant (AA) = p^{2} = (0.4)^{2} = 0.16 .Frequency of heterozygotes (A a) = 2 pq = 2 (0.4) (0.6) = 0.48 .Frequency of homozygous recessive (aa) = q^{2} = (0.6)^{2} = 0.36 .The correct sequence is 0.16 (AA); 0.48 (A a); 0.36 (aa) .

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A gene locus has two alleles A, a . If the frequency of dominant allele A is 0.4, then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population?

0.36 (AA); 0.48 (A a); 0.16 (aa)

0.16 (AA); 0.24 (A a); 0.36 (aa)

0.16 (AA); 0.48 (A a); 0.36 (aa)

0.16 (AA); 0.36 (A a); 0.48 (aa)

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