A group of 6 chairs and 3 tables together has 54 legs. If each chair has 4 legs, how many legs does one table have ?

Given:
* Total number of chairs = $6$
* Number of legs per chair = $4$
* Total legs of 6 chairs = $6\times 4=24$

Let the number of legs on one table be $t$.

* Total legs of 3 tables = $3t$

According to the problem:

$$\text{Total legs}=\text{Legs of chairs}+\text{Legs of tables}$$

$$54=24+3t$$

$$3t=54-24$$

$$3t=30$$

$$t=\frac{30}{3}=10$$

Thus, each table has $10$ legs.