A hemispherical bowl is made of a steel sheet 0.8 cm thick. The inside radius of the bowl is 5 cm . The volume of steel used in making it is approxima - Quantitative Aptitude MCQ WBCS Mains 2026 | ExamTest.live

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A hemispherical bowl is made of a steel sheet 0.8 cm thick. The inside radius of the bowl is 5 cm . The volume of steel used in making it is approximately:

Solution & Step-by-step Explanation

Given parameters: * Inner radius (r) = 5 cm * Thickness = 0.8 cm * Outer radius (R) = r + thickness = 5 + 0.8 = 5.8 cm The volume of material used for a hollow hemisphere is given by: Volume = \frac{2}{3} π (R^{3} - r^{3}) Calculate R^{3} and r^{3} : R^{3} = (5.8)^{3} = 195.112 cm^{3} r^{3} = (5)^{3} = 125 cm^{3} R^{3} - r^{3} = 195.112 - 125 = 70.112 cm^{3} Now, compute the volume: Volume = \frac{2}{3} \times \frac{22}{7} \times 70.112 = \frac{44}{21} \times 70.112 \approx 146.9 cm^{3}

Try it yourself before checking the explanation above.

A hemispherical bowl is made of a steel sheet 0.8 cm thick. The inside radius of the bowl is 5 cm . The volume of steel used in making it is approximately:

146,\text{cm}^3

144.9,\text{cm}^3

146.9,\text{cm}^3

148.6,\text{cm}^3

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