A is 40% more efficient than B. If B alone can complete a work in 42 days, then A alone can complete the same work in how many days?
- A36
- B40
- C30
- D32
Solution & Step-by-step Explanation
Let the efficiency of B be 100.
Since A is 40% more efficient than B, the efficiency of A is:
100+40=140
The ratio of efficiency of A to B is:
Efficiency of B
Efficiency of A
=
100
140
=
5
7
Time taken is inversely proportional to efficiency:
Time taken by B
Time taken by A
=
Efficiency of A
Efficiency of B
42
Time taken by A
=
7
5
Time taken by A=
7
5
×42=5×6=30 days
Since A is 40% more efficient than B, the efficiency of A is:
100+40=140
The ratio of efficiency of A to B is:
Efficiency of B
Efficiency of A
=
100
140
=
5
7
Time taken is inversely proportional to efficiency:
Time taken by B
Time taken by A
=
Efficiency of A
Efficiency of B
42
Time taken by A
=
7
5
Time taken by A=
7
5
×42=5×6=30 days