A is 40% more efficient than B. If B finishes a work in 14 days, then in how many days will A finish the same work?
- A10.5
- B9
- C8.4
- D10
Solution & Step-by-step Explanation
Let the efficiency of B be 100 units/day.
Since A is 40% more efficient than B, the efficiency of A is:
100+40=140 units/day
The ratio of efficiency of A to B is:
Efficiency of B
Efficiency of A
=
100
140
=
5
7
Total work = Efficiency of B × Number of days taken by B
Total Work=5×14=70 units
Number of days taken by A to complete the work:
Days taken by A=
Efficiency of A
Total Work
=
7
70
=10 days
Since A is 40% more efficient than B, the efficiency of A is:
100+40=140 units/day
The ratio of efficiency of A to B is:
Efficiency of B
Efficiency of A
=
100
140
=
5
7
Total work = Efficiency of B × Number of days taken by B
Total Work=5×14=70 units
Number of days taken by A to complete the work:
Days taken by A=
Efficiency of A
Total Work
=
7
70
=10 days