A laboratory has to pay Rs. 67.50 for 30 days as a gas bill if it uses 35 gas burners for 6 hours a day. Find

Question

A laboratory has to pay Rs. 67.50 for 30 days as a gas bill if it uses 35 gas burners for 6 hours a day. Find the amount to be paid if it uses 30 gas burners for 18 days working 7 hours a day.

Accepted Answer

The cost is directly proportional to the total consumption time, which depends on the number of burners (

B

), number of days (

D

), and hours per day (

H

).

\frac{Cost _{1}}{B _{1} \times D _{1} \times H _{1}} = \frac{Cost _{2}}{B _{2} \times D _{2} \times H _{2}}

Given values:

*

Cost_{1} = 67.50

,

B_{1} = 35

,

D_{1} = 30

,

H_{1} = 6

*

B_{2} = 30

,

D_{2} = 18

,

H_{2} = 7

Substituting the values:

\frac{67.50}{35 \times 30 \times 6} = \frac{Cost _{2}}{30 \times 18 \times 7}

Cost_{2} = \frac{67.50 \times 30 \times 18 \times 7}{35 \times 30 \times 6}

Simplifying the equation:

Cost_{2} = \frac{67.50 \times 18 \times 7}{35 \times 6}

Cost_{2} = \frac{67.50 \times 3 \times 1}{5}

Cost_{2} = 13.50 \times 3 = Rs. 40.50

A laboratory has to pay $Rs. 67.50$ for $30$ days as a gas bill if it uses $35$ gas burners for $6 hours$ a day. Find the amount to be paid if it uses $30$ gas burners for $18$ days working $7 hours$ a day.

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A laboratory has to pay Rs. 67.50 for 30 days as a gas bill if it uses 35 gas burners for 6hours a day. Find the amount to be paid if it uses 30 gas burners for 18 days working 7hours a day.