A lizard, at an initial distance of 21 cm behind an insect, moves from rest with an acceleration of 2 cm/s^2 and pursues the insect which is crawling - Mathematics MCQ AIEEE 2026 | ExamTest.live

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A lizard, at an initial distance of 21 cm behind an insect, moves from rest with an acceleration of 2 cm/s^{2} and pursues the insect which is crawling uniformly along a straight line at a speed of 20 cm/s . Then the lizard will catch the insect after:

Solution & Step-by-step Explanation

Distance of insect from start after time t : D_{i} = 21 + 20 t .Distance of lizard from start after time t : D_{l} = 0 + \frac{1}{2} a t^{2} = \frac{1}{2} (2) t^{2} = t^{2} .For lizard to catch insect, D_{l} = D_{i} : t^{2} = 21 + 20 t t^{2} - 20 t - 21 = 0 (t - 21) (t + 1) = 0 Since time cannot be negative, t = 21 s .

Try it yourself before checking the explanation above.

A lizard, at an initial distance of 21 cm behind an insect, moves from rest with an acceleration of 2 cm/s^{2} and pursues the insect which is crawling uniformly along a straight line at a speed of 20 cm/s . Then the lizard will catch the insect after:

20 s

1 s

21 s

24 s

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