A man on a tour travels the first $120\text{km}$ at $60\text{km/h}$ and the next $12\text{km}$ at $80\text{km/h}$. What is the average speed of the journey?

1. Find the time taken for the first part of the journey:
$$t_1=\frac{{\text{Distance}}_1}{{\text{Speed}}_1}=\frac{120}{60}=2\text{ hours}$$

2. Find the time taken for the second part of the journey:

$$t_2=\frac{{\text{Distance}}_2}{{\text{Speed}}_2}=\frac{12}{80}=0.15\text{ hours}$$

3. Calculate the total distance and total time:

$$\text{Total Distance}=120+12=132\text{km}$$

$$\text{Total Time}=2+0.15=2.15\text{ hours}$$

4. Compute the average speed:

$$\text{Average Speed}=\frac{\text{Total Distance}}{\text{Total Time}}=\frac{132}{2.15}\approx 61.3953\text{km/h}\approx 61.39\text{km/h}$$